FORM 2
THE PATENT ACT 1970
&
THE PATENT RULES,  2003
COMPLETE SPECIFICATION
(  See section 10 and rule 13  )

1 :-  TITLE OF INVENTION : - Curiosity Power
2 :-  APPLICANT
( a )  NAME : -  Haribhai Jeshangbhai Desai
( b )  NATIONALITY : -  INDIAN
( c )  ADDRESS  : -  Mahadev vas,  At & Po :-  Kheralu 384325 , Dist:-                                                                Mehsana, Gujarat, India
3 :-  The following specification particularly describes the invention and the                                 manner in which it is to be performed.

4. Description :-

Curiosity Power is a  "perpetual motion machine". Tt is a mechanical process of compressed air and water in the manner that produce electrical power without any type of fuel. It is a technique that output become more than input. The aim of Curiosity power is to provide ample, cheaper, endless and at door clean electrical power. It is a way to stop climate change, and poverty at a time.

See Figure -1 and keep in your hand.In Figure - 1a there are two identical steel tanks. Each with four valves. two valves for air inlet outlet and two valves for water inlet outlet. The right hand tank is empty. Let left hand 13 m3 tank is filled with 25bar air and all valves are closed. The energy formula E = P * V.  Now open valve - A. Air rush into right tank. As per Robert Boyle's law E = P * V = P/2 * 2V.

Now see Figure - 1b, The right side tank is filled with water. The diameter of valve- B is 2.45 c.m. , Now open valve - A and valve - B at a time.The tank water evacuate and form water jet at valve - B. When water level come very nearer to bottom, close valve - B that air can not escape.

Now check The result. E = P/2 * 2V, same as Figure - 1a. To transfer the jet energy into electrical energy, there is turbine and generator. The generator produce net 5 Kwh at 75% efficiency of turbine and generator jointly. The diameter of valve - B is 2.45 c.m.,evacuate in 450 second. Now volume is 13+13=26 m3 and pressure is 12.5 bar remain.

Now see Figure - 2 ,there is AA line. Left to AA line there are two tanks, each with 13 m3.Total volume 26 m3 filled with air at 12.5 bar. At the right of line AA, a third tank filled with water, volume 26 m3 is joined by valve -  C. This is as per Figure - 1b. Now open valve - c and bottom valve - D at a time. The tank start evacuate and jet form at valve - D. When water level come very nearer to bottom, close valve - D, that air can not escape. The diameter of valve - D is 4.1 c.m.  The tank evacuate in 450 second. The generator produce net 5 Kwh as per figure - 1b. Now the pressure in all tanks is 6.25 bar and volume 52 m3. The formula become E = P * V = P/2 * 2V = P/4 * 4V

In this operation, we produced 5 Kwh of second tank + 5 Kwh of third tank = 10 Kwh power is power without fuel in 450 ( second tank ) + 450 ( third tank ) = 900 second. This power is without loss of original energy E of first tank.

Now see figure - 3.
Our main question is how to fill the first tank air at 25 bar. To solved the question, fill the first tank with water and remove the tank water by 25 bar compressed air. In starting the machine,  use external electrical energy to run compressor motor. let the compressor deliver 1.3 m3/ minute air at 25 bar. open valve - A and valve - D at a time. The jet produced at bottom valve - D. This jet energy is converted into electrical energy by turbine and generator. The combined efficiency of motor + compressor  and combined efficiency of turbine + generator is taken 75 %. The jet produce 6.64 Kwh in 10 minute. The diameter of valve - D is 2 c.m.

Now energy balance. The given energy to motor is 12 Kwh. The production of second tank is 5 Kwh and third tank 5 Kwh. ( see calculation given below ) . The production of energy 6.64 + 10 = 16.64 . The refilling 52 m3 water by 9 KW motor pump at 8 m height in 10 minute  need 1.5 Kwh. That reducing refilling energy,  16.64 - 1.5 = 15.14 Kwh. That  15.14 - 12 = 3.14 + E is the benefit, E = 9 Kwh. But we can convert only 33% of E into electrical energy by air motor. This is 3 Kwh. That the net benefit  3.14 + 3 = 6.14 . Note that the output is more than the input. This prove that Curiosity power is a perpetual motion machine

CALCULATIONS :-

1 :-     The volume of first tank :-
There are three variable, bottom valve diameter D, pressure P and evacuate             time T. Let D = 2 c.m.,  P = 25 bar, T = 600 second. The water flowing  Q m3/second           = Aria * velocity = 3.14 / 4 *( D )2 * ( 2 * g * H )0.5 = 3.14 / 4 * ( 0.02 )2 * ( 2 * 9.81 *             250 )0.5 = 0.022 m3 / second.The water flow for 10 minute = 600 second, that Q                   m3 = .022 * 600 = 13.2 m3 . Let take approximate volume = 13 m3.

2 :-     The energy into first tank.:-
The Energy E = 25 *105 N / m2 * 13 m3 = 32500 KJ  But 3600 KJ = 1 Kwh,               that 32500 / 3600 = 9 Kwh

3 :-     The size ( KW ) of compressor motor :-
This E = 32500 KJ came in 600 second, That 32500 / 600 = 54 KW, for 75%             efficiency of compressor + motor, that 54 * ( 100 / 75 ) = 72 KW. This 72 KW motor               run for 10 minute consume 72 * 10 / 60 = 12 Kwh. First time starting the machine, 12           Kwh external electrical energy needed.

4 :-     The size ( KW ) of electrical power generator :-
Considering 75% efficiency at compressor+motor side and same 75 % at                 turbine + generator side,  The total efficiency 0.75 * 0.75 = 0.56 %,That 72 * 0.56 =               40.5 KW, That it generate in 10 minute 40.5 * 10 / 60 = 6.75 Kwh. The cost of air = 12           - 6.75 = 5.25 Kwh.

5 :-     The evacuating time and the bottom diameter of second tank.:-
In second tank the starting pressure is 25 bar and at end pressure is 12.5 bar.           That everage is 18.75 bar.The torque  to run generator 40.5 KW must be maintained.           KW * 100 / 75 = mgh /  ( t * 1000 ) ,  KW = 40.5, h = ( 25 + 12.5 ) / 2 = 18.75 * 10                  m.=187.5 m.  .m =13000 , g = 9.81 . That t = 443 second, we consider 450 second =           7.5 minute.That power generation 40.5 * 7.5 / 60 = 5 Kwh  and bottom diameter =                  2.46 c.m.

6 :-     The third tank bottom diameter = 4.1 c.m. and the power generation is as equal                    second tank = 5 Kwh, Evacuating time = 7.5 minute.

Figure :- 4
Figure:- 4 is the plan of figure:- 3.  One set of three tanks complete one cycle in 40 minutes. This 40 minute include evacuating time of all tanks + air motor + refilling time. That to continue the power production, there is need of total 4 tanks set, one behind other as shown in Figure :- 4 . The 4 set produce 4 time power. In this case 6.14 * 4 = 24.56 Kwh in 40 minutes. That in one hour 24.56 * 1.5 = 36.84 Kwh. Yearly production 36.84 * 24 * 365 = 322718 Kwh. If the first tank volume is 130 m3, Then the power production will be 10 times means 3227180 , Approximately 3 million Kwh . To my understanding  this power cost 30 paisa / Kwh. in India.

5         I claim
1 :- The Curiosity power is the world's first perpetual motion machine.
2 :- The Curiosity power is a new non conventional method of electrical                                  power production.

6         Dated this on 14 may 2019

Signature

7 :-         Abstract of the Invention :-
The perpetual motion machine was said " impossible " is become " possible by this invention. Now electrical power production will be easy,cheaper and without fuel. Now no need of gas cylinder in home for cooking, because electricity become too cheap. This remove climate change and poverty problems.    FORM   2
THE PATENTS ACT ,1970
(39 OF 1970)
COMPLETE SPECIFICATION
(See section 10)

1.    TITLE : Reaction  Power
2.   Name And Address :- Desai Haribhai J.
At & Post :- KHERALU-384325
Dist :- Mehsana , Gujarat State, India
E-mail :- desaihari@ymail.com
Nationality :- INDIAN

The following specification particularly describes the nature of invention and the manner in which it is to be performed.................

3.   The " Reaction Power " is a technique to increase the hydro-electrical power production by using Newton's third law of motion. The law is " The action and reaction are equal and opposite." It is a mechanical process to increase hydro-electrical power production approximately double. Moreover the low head water reseovers ( Dam ) can produce electrical power. Nowadays the world wide hydro-electrical power stations are using  only  " the action " of water jets of high head water ( Dam water ). In this process ( technique ), both " the action " and it's " reaction " of a water jet is used.  In this way the power production increased approximately double. The low head dam water is made high head by application of an electrical motor and the water can be used to produce power.

Go to Figure :-- 1,
a ,-   Dam - Store water in monsoon , b ,- Motor - Used to increase the head of dam water. It's section is in the dam or dam side and delivery to the drum side.    c,-  Penstock is a pipe drawing water from dam to drum. d ,- Air Vessel to control the fluctuation in pressure in the system. e,- Rotating joint permit drum rotation. f ,- Drum is on bearings with pulley and jet pipes  g ,- Jets pipes discharge the water at right angle to the radius of drum that the drum receives maximum rotational thrust. h ,- Pelton turbines are set to suit the jets for maximum output. Pelton turbines are joint with generators.  This is a planetary electrical power production. i ,- Rings are fixed and get power from rotating generators. j ,- Drum generator empowers by drum pulley.

To start the power plant, first start the motor by external electrical power. May be taken from an electrical power company.  Then run the motor for two minutes. Now our power plant production starts. Then by change over switch, cutoff  external power and use our power.
Working : --
I distingulate the dams in two categories.   ( a ) : - High water head dames where the Pelton turbines work easily. It can produce double power by application of drum and the jet reaction.  ( b) :- Low water head dams where Pelton turbines do not work. It needs motor action to raise the water head in the penstock. Note that whatever power given to motor is recovered.

The Plton turbines are designed to work at high water heads and low quantities of water. To be more clear I give an example of a low water head ( 10 m ) dam power plant. The location of the dam is At : - Dharoi, Tehsil :- Satlasana, Dist : - Mehsana, Gujarat State, India . It provides 22 m^3/second water from September to April for irrigation needs.  The dam water passes through penstock, motor, rotating joint,drum, jet pipes jets and discharge. The water jets give the kinetic energy to Pelton turbines and the reaction energy to the drum to rotate. The Pelton turbines produce electricity transfer by fixed rings. The drum generator is empowered by drum pulley and belts. Here I do not discuss electrical engineering.

To be more clear, when 100 kw motor is applied, it gives 100 x 70 % = 70 kw to the penstock water to increase the head. This 70 kW goes to Pelton turbines. The both Pelton turbines give 70 x 80% = 56 kw. The drum generator gives 70 x 80% = 56kw.The benefit is 56 + 56 = 112 kw - 100 kw = 12 kw, means 12% benefit by application of motor. In This way if the motor applied 1000 kw, then the benefit will be 120 kw.  Means 12% benefit by application of motor. Note that one has to apply a minimum kw of motor  that Pelton turbines efficiently produce power.  Graphically, the benefit in kw on Y- axis and applied motor kw on X- axis, the graph is a straight line inclined 50 degree to the X- axis. The motor is essential to all type dams in this " Reaction Power " research.

Example and Calculations : --
The data of low head dam : --  Head H = 10 m and Q = 22 m^3/second For calculation I take part of the water Q=1.2 m^3/ second for easy calculation and understanding.
water power = d Q g H  where d is density of water, and g is a gravity.  Therefore water power = 1000 x 1.2 x 9.81 x 10 = 117720 watt.   Means 117.72 kw.

Now I apply a 1545 kw motor to raise the head  H = 100m .  Take overall efficiency of motor 70 %, Overall efficiency of Peton turbine 80%, Overall efficiency of drum generator 80%,  Overall efficiency contains all types of losses, may be by  friction, by hydraulic losses, etc.  Now the actual motor gives 1545 x 70% = 1081.5 kW to the system. That the Pelton turbines gives 1081.5 x 80 % = 865.2 kw. The drum generator gives 1081.5 x80 % = 865.2 kw. Total power generation 865.2 + 865.2 = 1730.4 kw.  That the motor benefits 1730.4 - 1545 = 185.4, The benefit is 12 % of applied motor power.

Now total water power is = water power + benefit power = 117.72 +185.4 =203.12 kw. That total dam power = 203.12 ( 22 / 1.2 ) = 3723 kw . Now I have my own water and power to start the second set of power plants.  This is said to be a 3.723 MW plant.

4 :--  Claim :-  ( 1 )  The world wide hydro-electric power production can be made double and the low head dam can be enable to produce electrical power.

5 :-   Abstract :-    This is clean / green production and reduces climate change problems. This extra power production is  very
cheap that help to remove poverty. 